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3(x^2+5)=12x
We move all terms to the left:
3(x^2+5)-(12x)=0
We add all the numbers together, and all the variables
-12x+3(x^2+5)=0
We multiply parentheses
3x^2-12x+15=0
a = 3; b = -12; c = +15;
Δ = b2-4ac
Δ = -122-4·3·15
Δ = -36
Delta is less than zero, so there is no solution for the equation
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